Differentiation Question 438
Question: If $ y=\log x^{x}, $ then $ \frac{dy}{dx}= $
[MNR 1978]
Options:
A) $ x^{x}(1+\log x) $
B) $ \log (ex) $
C) $ \log ( \frac{e}{x} ) $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ y=\log x^{x}=x\log x $
Differentiating w.r.t. x, we get $ \frac{dy}{dx}=(1+\log x)=\log e+\log x=\log (ex) $
$ (\because \log e=1) $ .
BETA
