Differentiation Question 452
Question: For the curve $ \sqrt{x}+\sqrt{y}=1,\frac{dy}{dx} $ at $ ( \frac{1}{4},\frac{1}{4} ) $ is
[Karnataka CET 1993]
Options:
A) ½
B) 1
C) -1
D) 2
Show Answer
Answer:
Correct Answer: C
Solution:
$ \sqrt{x}+\sqrt{y}=1 $
Therefore $ \frac{dy}{dx}=-\frac{\sqrt{y}}{\sqrt{x}} $
Therefore $ {{( \frac{dy}{dx} )} _{( \frac{1}{4},\frac{1}{4} )}}=-1 $ .
BETA
