Differentiation Question 47

Question: If $ f(x)=e^{x}g(x),g(0)=2,g’(0)=1 $ , then $ f’(0) $ is

Options:

A) 1

B) 3

C) 2

D) 0

Show Answer

Answer:

Correct Answer: B

Solution:

$ f(x)=e^{x}g(x)\Rightarrow f’(x)=e^{x}g(x)+e^{x}g’(x) $

$ \Rightarrow f’(0)=g(0)+g’(0)=2+1=3 $ .