Differentiation Question 47
Question: If $ f(x)=e^{x}g(x),g(0)=2,g’(0)=1 $ , then $ f’(0) $ is
Options:
A) 1
B) 3
C) 2
D) 0
Show Answer
Answer:
Correct Answer: B
Solution:
$ f(x)=e^{x}g(x)\Rightarrow f’(x)=e^{x}g(x)+e^{x}g’(x) $
$ \Rightarrow f’(0)=g(0)+g’(0)=2+1=3 $ .