Differentiation Question 48
Question: If then $ \frac{dy}{dx} $ is
Options:
A) $ \frac{2xy}{2y-x^{2}} $
B) $ \frac{xy}{y+x^{2}} $
C) $ \frac{xy}{y-x^{2}} $
D) $ \frac{2xy}{2+{{\frac{x}{y}}^{2}}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ y=x^{2}+\frac{1}{y} $ Or $ y^{2}=x^{2}y+1 $ Or $ 2y\frac{dy}{dx}=y.2x+x^{2}\frac{dy}{dx} $ Or $ \frac{dy}{dx}=\frac{2xy}{2y-{x^{2.}}} $
BETA
