Differentiation Question 54

Question: If $ y=e^{x}\log x $ , then $ \frac{dy}{dx} $ is

[SCRA 1996]

Options:

A) $ \frac{e^{x}}{x} $

B) $ e^{x}( \frac{1}{x}+x\log x ) $

C) $ e^{x}( \frac{1}{x}+\log x ) $

D) $ \frac{e^{x}}{\log x} $

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Answer:

Correct Answer: C

Solution:

Differentiating $ y=e^{x}\log x, $ w.r.t. x ,we get $ \frac{dy}{dx}=e^{x}\times \frac{1}{x}+\log x\times e^{x}=e^{x}( \frac{1}{x}+\log x ) $ .