Differentiation Question 54
Question: If $ y=e^{x}\log x $ , then $ \frac{dy}{dx} $ is
[SCRA 1996]
Options:
A) $ \frac{e^{x}}{x} $
B) $ e^{x}( \frac{1}{x}+x\log x ) $
C) $ e^{x}( \frac{1}{x}+\log x ) $
D) $ \frac{e^{x}}{\log x} $
Show Answer
Answer:
Correct Answer: C
Solution:
Differentiating $ y=e^{x}\log x, $ w.r.t. x ,we get $ \frac{dy}{dx}=e^{x}\times \frac{1}{x}+\log x\times e^{x}=e^{x}( \frac{1}{x}+\log x ) $ .