A) $ x{{\tan }^{-1}}x $
B) $ 2{{\tan }^{-1}}x $
C) $ 2x{{\tan }^{-1}}x+1 $
D) $ x{{\tan }^{-1}}x+1 $
Correct Answer: C
$ \frac{d}{dx}[(1+x^{2}){{\tan }^{-1}}x]=1+2x{{\tan }^{-1}}x $ .
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