A) $ x^{2}\frac{dy}{dx}+xy=0 $
B) $ x^{2}\frac{dy}{dx}+xy+2=0 $
C) $ x^{2}\frac{dy}{dx}-xy+2=0 $
D) None of these
Correct Answer: C
$ y=x+\frac{1}{x} $
Therefore $ \frac{dy}{dx}=1-\frac{1}{x^{2}} $
Therefore, $ x^{2}.\frac{dy}{dx( 1-\frac{1}{{}} )}-xy+2=x^{2} $
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