Differentiation Question 65
Question: If $ y=\sqrt{\sin \sqrt{x}} $ , then $ \frac{dy}{dx}= $
[MP PET 1997]
Options:
A) $ \frac{1}{2\sqrt{\cos \sqrt{x}}} $
B) $ \frac{\sqrt{\cos \sqrt{x}}}{2x} $
C) $ \frac{\cos \sqrt{x}}{4\sqrt{x}\sqrt{\sin \sqrt{x}}} $
D) $ \frac{1}{2\sqrt{\sin x}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{dy}{dx}=\frac{1}{2\sqrt{\sin \sqrt{x}}}\times \cos \sqrt{x}\times \frac{1}{2\sqrt{x}} $ .
BETA
