Differentiation Question 9
Question: If $ x^{y}.y^{x}=1 $ , then $ \frac{dy}{dx} $ =
Options:
A) $ \frac{y(y+x\log y)}{x(y\log x+x)} $
B) $ \frac{y(x+y\log x)}{x(y+x\log y)} $
C) $ -\frac{y(y+x\log y)}{x(x+y\log x)} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ y\log x+x\log y=0 $ ;
$ \therefore $ $ \frac{dy}{dx}=\frac{\partial f/\partial x}{\partial f/\partial y} $ .
BETA
