Equations And Inequalities Question 10
Question: The solution set of the inequality $ 37-(3x+5)\ge 9x-8(x-3) $ is
Options:
A) $ (-\infty ,2) $
B) $ (-\infty ,-2) $
C) $ (-\infty ,2] $
D) $ (-\infty ,-2] $
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Answer:
Correct Answer: C
Solution:
- [c] We have, $ 37-(3x+5)\ge 9x-8(x-3) $ $ (37-3x-5)\ge 9x-8x+24 $
$ \Rightarrow 32-3x\ge x+24 $ Transferring the term 24 to L.H.S. and the term $ (-3x) $ to R.H.S. $ 32-24\ge x+3x\Rightarrow 8\ge 4x\Rightarrow 4x\le 8 $ Dividing both sides by 4. $ \frac{4x}{4}\le \frac{8}{4}\Rightarrow x\le 2 $
$ \therefore $ Solution set is $ (-\infty ,2]. $
BETA
