Equations And Inequalities Question 14
Question: The set of real values of x satisfying $ | x-1 |\le 3 $ And $ | x-1 |\ge 1 $ is
Options:
A) $ [2,4] $
B) $ (-\infty ,2]\cup [4,+\infty ) $
C) $ [-2,0]\cup [2,4] $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- [c] $ | x-1 |\le 3\Rightarrow -3\le x-1\le 3\Rightarrow -2\le x\le 4 $ and $ | x-1 |\ge 1\Rightarrow x-1\le -1orx-1\ge 1\Rightarrow x\le 0 $ $ orx\ge 2 $ Taking the common values of x, we get $ x\in [-2,0]\cup [2,4] $
BETA
