Equations And Inequalities Question 4
Question: Solution set of the inequality $ {\log_3}(x+2)(x+4)+lo{g_{1/3}}(x+2)<\frac{1}{2}\log \sqrt{3}7,(1) $ is
Options:
A) $ (-2,-1) $
B) $ (-2,3) $
C) $ (-1,3) $
D) $ (3,\infty ) $
Show Answer
Answer:
Correct Answer: B
Solution:
- [b] $ (x+2)(x+4)>0.x+2>0\Rightarrow x>-2. $ Now (1) can be written as $ {\log_3}(x+2)(x+4)-log_3(x+2)<\frac{(log7)/2}{(log3)/2} $
$ \Rightarrow {\log_3}(x+4)<log_3^{7}\Rightarrow x+4<7orx<3. $
BETA
