Equations And Inequalities Question 45
Question: The solution set of $ \frac{2x-1}{3}\ge ( \frac{3x-2}{4} )-( \frac{2-x}{5} ) $ is $ (-\infty ,a] $ . The value of ?a? is
Options:
A) 2
B) 3
C) 4
D) 5
Show Answer
Answer:
Correct Answer: A
Solution:
- [a] $ \frac{2x-1}{3}\ge \frac{15x-10-8+4x}{20} $
$ \Rightarrow ,\frac{2x-1}{3}\ge \frac{19x-18}{20} $
$ \Rightarrow 40x-20\ge 57x-54\Rightarrow -17x\ge -34\Rightarrow x\le 2 $
$ \Rightarrow ,x\in (-\infty ,2] $
BETA
