Functions Question 123
Question: $ \underset{x\to 0}{\mathop{\lim }},\frac{1-\cos x}{{{\sin }^{2}}x}= $
[DSSE 1987]
Options:
A) $ \frac{1}{2} $
B) $ -\frac{1}{2} $
C) 2
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{x\to 0}{\mathop{\lim }}\frac{2,{{\sin }^{2}}\frac{x}{2}.,(x^{2})}{4,{{\sin }^{2}}x,.,( \frac{x^{2}}{4} )}=\frac{1}{2}. $ Aliter : Apply L-Hospital?s rule two times.
BETA
