Functions Question 129
Question: $ \underset{x\to 0}{\mathop{\lim }},\frac{1-\cos 6x}{x}= $
[DSSE 1982]
Options:
0
6
C) $ \frac{1}{3} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{x\to 0}{\mathop{\lim }}\frac{1-\cos 6x}{x}=\underset{x\to 0}{\mathop{\lim }}\frac{2{{\sin }^{2}}3x}{x}=\underset{x\to 0}{\mathop{\lim }}\frac{2{{\sin }^{2}}3x}{x}=\underset{x\to 0}{\mathop{\lim }}\frac{2{{\sin }^{2}}3x}{x}=0 $
BETA
