Functions Question 140
Question: $ f(x)=x+\sqrt{x^{2}} $ is a function from R $ \to $ R , then $ f(x) $ is
[Orissa JEE 2004]
Options:
A) Injective
B) Surjective
C) Bijective
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
We have $ f(x)=x+\sqrt{x^{2}}=x+|x| $ Clearly f is not one-one as $ f(-1)=f(-2)=0 $ but $ -1\ne 2 $ . Also f is not onto as $ f(x)\ge 0,,\forall x\in R, $ Also, range of $ f=(0,\infty )\subset R $ .
BETA
