Functions Question 150
Question: $ \underset{x\to \frac{\pi }{2}}{\mathop{\lim }},|(1-\sin x)\tan x $ is
Options:
A) $ \frac{\pi }{2} $
B) 1
C) 0
D) $ \infty $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{x\to \pi /2}{\mathop{\lim }}{ (1-\sin x)\tan x }=\underset{x\to \pi /2}{\mathop{\lim }}\frac{\sin x-{{\sin }^{2}}x}{\cos x} $ Apply L-Hospital?s rule, we get $ \underset{x\to \pi /2}{\mathop{\lim }}\frac{\cos x-\sin 2x}{-\sin x}=0 $ .
BETA
