Functions Question 184
Question: The value of $ \underset{x\to \infty }{\mathop{\lim }},\frac{\log x}{x^{n}},\ n>0 $ is
Options:
A) $ 0 $
B) $1$
C) $ \frac{1}{n} $
D) $ \frac{1}{n!} $
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Answer:
Correct Answer: A
Solution:
$ \underset{x\to \infty }{\mathop{\lim }}\frac{\log x}{x^{n}}=\underset{x\to \infty }{\mathop{\lim }}\frac{1}{nx^{n-1}}=0 $ (By L-Hospital’s rule)
BETA
