[SCRA 1996]
A) $ \frac{2}{3} $
B) $ 1 $
C) 0
D) $ \infty $
Correct Answer: A
$ \underset{x\to ,\infty }{\mathop{\lim }},\frac{2x^{2}+3x+4}{3x^{2}+3x+4}=\underset{x\to \infty }{\mathop{\lim }},\frac{2+\frac{3}{x}+\frac{4}{x^{2}}}{3+\frac{3}{x}+\frac{4}{x^{2}}}=\frac{2}{3} $ .
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