Functions Question 219
Question: Function $ f(x)= \begin{cases} & ,x-1,\ x<2 \\ & 2x-3,,x\ge 2 \\ \end{cases} . $ is a continuous function
[MP PET 1996]
Options:
A) For all real values of x
B) For $ x=2 $ only
C) For all real values of x such that $ x\ne 2 $
D) For all integral values of x only
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ \underset{x\to 2-}{\mathop{\lim }},f(x)=\underset{x\to 2+}{\mathop{\lim }},f(x)=f(2)=1 $ Also it is continuous for all values of x, less than 2 and greater than 2.
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