Functions Question 240
Question: The value of $ \underset{x\to 0}{\mathop{\lim }}( \frac{e^{x}-1}{x} ) $ is
[Karnataka CET 2001]
Options:
A) 1/2
B) $ \infty $
C) 1
D) 0
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{x\to 0}{\mathop{lim}},\frac{e^{x}-1}{x}=\underset{x\to 0}{\mathop{lim}},\frac{( 1+\frac{x}{1!}+\frac{x^{2}}{2!}+…-1 )}{x}=1 $ .
BETA
