SATHEE: Functions Question 268

Functions Question 268

Question: If $ f(x)=e^{2x} $ and $ g(x)=\log \sqrt{x} $ $ (x>0) $ , then $ fog(x) $ is equal to

Options:

A) $ e^{2x} $

B) $ \log \sqrt{x} $

C) $ e^{2x}\log \sqrt{x} $

D) x

Show Answer

Answer:

Correct Answer: D

Solution:

$ fog,(x)=f{g(x)}={e^{2\log \sqrt{x}}}=x. $

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Functions Question 268

Question: If $ f(x)=e^{2x} $ and $ g(x)=\log \sqrt{x} $ $ (x>0) $ , then $ fog(x) $ is equal to

Options:

Answer:

Solution:

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