Functions Question 28
Question: $ \underset{x\to \pi /2}{\mathop{\lim }},\tan x\log \sin x= $
[MNR 1989]
Options:
A) 0
B) 1
C) ?1
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{x\to \frac{\pi }{2}}{\mathop{\lim }}\tan x\log ,\sin x=\underset{x\to \frac{\pi }{2}}{\mathop{\lim }},\frac{\log \sin x}{\cot x} $ $ =\underset{x\to \frac{\pi }{2}}{\mathop{\lim }},\frac{\frac{1}{\sin x}\cos x}{-cose{c^{2}}x}=0 $ (Applying L-Hospital?s rule)
BETA
