Functions Question 281
Question: $ \underset{x\to \pi /6}{\mathop{\lim }},
[ \frac{3\sin x-\sqrt{3}\cos x}{6x-\pi } ]= $ [EAMCET 2003]
Options:
A) $ \sqrt{3} $
B) $ 1/\sqrt{3} $
C) $ -\sqrt{3} $
D) $ -1/\sqrt{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
Using L?Hospital?s rule, $ \underset{x\to \pi /6}{\mathop{\lim }},\frac{3\cos x+\sqrt{3}\sin x}{6}=\frac{3.\frac{\sqrt{3}}{2}+\sqrt{3}.\frac{1}{2}}{6}=\frac{1}{\sqrt{3}} $ .
BETA
