Functions Question 283
Question: . $ \underset{x\to 0}{\mathop{\lim }},\frac{\cos (\sin x)-1}{x^{2}}= $
[Orissa JEE 2003]
Options:
A) 1
B) ? 1
C) ½
D) ?1/2
Show Answer
Answer:
Correct Answer: D
Solution:
$ \underset{x\to 0}{\mathop{lim}},\frac{\cos (\sin x)-1}{x^{2}} $ = $ \underset{x\to 0}{\mathop{lim}},\frac{-2{{\sin }^{2}}( \frac{\sin x}{2} )}{x^{2}}=-2.\frac{1}{4}=\frac{-1}{2} $ .
BETA
