Functions Question 311
Question: The domain of the function $ f(x)={{\sin }^{-1}}
[{\log_2}(x/2)] $ is [RPET 2002]
Options:
A) [1, 4]
B) [?4, 1]
C) [?1, 4]
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ f(x)={{\sin }^{-1}}[{\log_2}(x/2)] $ , Domain of $ {{\sin }^{-1}}x $ is $ x\in [-1,,1] $
Þ $ -1\le {\log_2}(x/2)\le 1 $
Þ $ \frac{1}{2}\le \frac{x}{2}\le 2 $
Þ $ 1\le x\le 4 $ \ $ x\in [1,,4] $ .
BETA
