Functions Question 348
Question: If $ R={x,y}:x,y\in I $ and $ x^{2}+y^{2}\le 4} $ is a relation in I, the domain of R is
Options:
A) $ {0,1,2} $
B) $ {-2,-1,0} $
C) $ {-2,-1,0,,1,2} $
D) I
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ x^{2}+y^{2}\le 4 $ , represents all points interior to the circle $ x^{2}+y^{2}=4, $ hence $ -2\le x\le 2 $ and $ -2\le y\le 2 $
$ \therefore $ integral values of x are $ -2,-1,0,1,2 $
BETA
