Functions Question 356
Question: The domain and range of the relation R given by $ R={(x,y):y=x+\frac{6}{x};} $ where $ x,y\in N $ and $ x<6 $ is
Options:
A) $ {1,2,3},{7,5} $
B) $ {1,2},{7,5} $
C) $ {2,3},{5} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] When $ x=1,y=7\in N,so(1,7)\in R $ when $ x=2,y=2+3=5\in N,so(2,5)\in R $ Again for $ x=3,y=3+2=5\in N,(3,5)\in R $ similarly for $ x=4,y=4+\frac{6}{4}\notin N $ and for x = 5, $ y=5+\frac{6}{5}\notin N. $ Thus, $ R={(1,7),(2,5),(3,5)} $
$ \therefore $ Domain of $ R={1,2,3} $ and Range of $ R={7,5}. $
BETA
