A) $ a/b $
B) $ b/a $
C) 1
D) None of these
Correct Answer: A
$ \underset{x\to 0}{\mathop{\lim }}\frac{\sin ax}{\sin bx}=\underset{x\to 0}{\mathop{\lim }}\frac{a}{b}\frac{\sin ax}{ax}\frac{bx}{\sin bx}=\frac{a}{b} $ .
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