Functions Question 385
Question: The domain of the function $ f(x)={\log_{3+x}}(x^{2}-1) $ is
[Orissa JEE 2003]
Options:
A) $ (-3,\ -1)\cup (1,\ \infty ) $
B) $ [-3,\ -1)\cup [1,\ \infty ) $
C) $ (-3,\ -2)\cup (-2,\ -1)\cup (1,\ \infty ) $
D) $ [-3,\ -2)\cup (-2,\ -1)\cup [1,\ \infty ) $
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Answer:
Correct Answer: C
Solution:
$ f(x) $ is to be defined when $ x^{2}-1>0 $
Þ $ x^{2}>1, $
Þ $ x<-1\text{ or }x>1 $ and $ 3+x>0 $ \ $ x>-3 $ and $ x\ne -2 $ \ $ D_{f}=(-3,,-2)\cup (-2,,-1)\cup (1,,\infty ) $ .
BETA
