Functions Question 412
Question: If from $ R\to R $ , $ f(x)={{(x+1)}^{2}} $ , $ g(x)=x^{2}+1 $ , then $ (fog)(-3) $ equals
[RPET 1999]
Options:
A) 121
B) 112
C) 211
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ f(x)={{(1+x)}^{2}} $  and  $ g(x)=x^{2}+1 $             and  $ fog(-3) $   $ =f[g(-3)]=f[9+1]=f[10] $          
Þ  $ fog(-3)=f[10]={{[11]}^{2}}=121 $ .
 BETA
  BETA 
             
             
           
           
           
          