Functions Question 428
Question: For the function $ f(x),=\frac{{\log_{e}}(1+x)-{\log_{e}}(1-x)}{x} $ to be continuous at $ x=0, $ the value of $ f(0), $ should be
[MP PET 2003]
Options:
A) ?1
B) 0
C) ?2
D) 2
Show Answer
Answer:
Correct Answer: D
Solution:
By L-Hospital?s rule $ \underset{x\to 0}{\mathop{\lim }},f(x) $ is 2. Therefore, for $ f(x) $ to be continuous, the value of function should be 2.
BETA
