Functions Question 439
Question: Let $ f(x)=[x], $ where $ [x] $ denotes the greatest integer less than or equal to x. if $ a=\sqrt{2011^{2}+2012} $ , then the value of fis equal to
Options:
A) 2010
B) 2011
C) 2012
D) 2013
Show Answer
Answer:
Correct Answer: B
Solution:
$ a=\sqrt{2011^{2}+2012}=2011.5; $ $ f(a)=\lfloor2011.5\rfloor=2011 $
BETA
