A) $ f(a+b) $
B) $ f(a-b) $
C) $ f(-a+b) $
D) $ f(-a-b) $
Correct Answer: D
[d] $ \frac{f(-a)}{f(b)}=\frac{e^{a}}{{e^{-b}}}=e^{a}e^{b}={e^{a+b}}={e^{-(-a-b)}} $ $ =f(-a-b) $
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