Functions Question 443
Question: If $ f(x)=\frac{x}{x-1}, $ then $ \frac{f(a)}{f(a+1)} $ is equal to:
Options:
A) $ f(a^{2}) $
B) $ f( \frac{1}{a} ) $
C) $ f(-a) $
D) $ f| \frac{-a}{a-1} | $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Given $ f(x)=\frac{x}{x-1}; $ Then, $ f(a)=\frac{a}{a=1} $ and $ f(a+1)=\frac{a+1}{a} $ So, $ \frac{f(a)}{f(a+1)}=\frac{a}{a-1}\times \frac{a}{a+1}=\frac{a^{2}}{a^{2}-1}=f(a^{2}) $
BETA
