Functions Question 455

Question: Let $ P=\{(x,y):| x^{2}+y^{2} |=1,x,y\in R\}. $ Then P is

Options:

A) Reflexive

B) Symmetric

C) Transitive

D) Anti-symmetric

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Obviously, the relation is not reflexive and transitive but it is symmetric, because $ x^{2}+y^{2}=1 $
$ \Rightarrow y^{2}+x^{2}=1 $