Functions Question 455
Question: Let $ P=\{(x,y):| x^{2}+y^{2} |=1,x,y\in R\}. $ Then P is
Options:
A) Reflexive
B) Symmetric
C) Transitive
D) Anti-symmetric
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Obviously, the relation is not reflexive and transitive but it is symmetric, because $ x^{2}+y^{2}=1 $
$ \Rightarrow y^{2}+x^{2}=1 $