Functions Question 455

Let $ P=\{(x,y):x^{2}+y^{2}=1,x,y\in R\}. $ Then P is

Options:

A) Reflexive

B) Symmetrical

C) Transitive relation

D) Anti-symmetric

Show Answer

Answer:

Correct Answer: B

Solution:

Obviously, the relation is not reflexive and transitive but it is symmetric, because $ x^{2}+y^{2} \leq 1 $ $ \Rightarrow y^{2}+x^{2}=1 $



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