Functions Question 455
Let $ P=\{(x,y):x^{2}+y^{2}=1,x,y\in R\}. $ Then P is
Options:
A) Reflexive
B) Symmetrical
C) Transitive relation
D) Anti-symmetric
Show Answer
Answer:
Correct Answer: B
Solution:
Obviously, the relation is not reflexive and transitive but it is symmetric, because $ x^{2}+y^{2} \leq 1 $ $ \Rightarrow y^{2}+x^{2}=1 $
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