Functions Question 491
A function f on R into itself is continuous at a point a in R, iff for each $ \epsilon >0 $ , there exists $ \delta >0 $ such that
[UPSEAT 2004]
Options:
A) $ |f(x)-f(a)|<\epsilon $ Þ $ |x-a|<\delta $
B) $ |f(x)-f(a)|>\epsilon $ Þ $ |x-a|>\delta $
C) $ |x-a|>\delta $ Þ $ |f(x)-f(a)|>\epsilon $
D) $ |x-a|<\delta $ Þ $ |f(x)-f(a)|<\epsilon $
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Answer:
Correct Answer: A
Solution:
It is evident.
BETA
