Functions Question 560
Question: Let $ f:(4,6)\to (6,8) $ be a function defined by $ f(x)=x+[ \frac{x}{2} ] $ (where [.] denotes the greatest integer function), then $ {f^{-1}}(x) $ is equal to
Options:
A) $ x-[ \frac{x}{2} ] $
B) $ -x-2 $
C) $ x-2 $
D) $ \frac{1}{x+[ \frac{x}{2} ]} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Since $ f:(4,6)\to (6,8)\Rightarrow f(x)=x+2 $
$ \therefore {f^{-1}}(x)=x-2 $
BETA
