Functions Question 601
Question: If $ f(x)= \begin{cases} & x^{2},when,x\ne 1 \\ & ,2,whenx=1 \\ \end{cases} . $ then
Options:
A) $ \underset{x\to 1}{\mathop{\lim }},f(x)=2 $
B) $ f(x) $ is continuous at $ x=1 $
C) $ f(x) $ is discontinuous at $ x=1 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{x\to 1}{\mathop{\lim }},f(x)=1,f(1)=2. $
BETA
