Functions Question 624
Question: If $ f(x)= \begin{cases} & x-1,,x<0 \\ & \frac{1}{4},x=0 \\ & ,x^{2},x>0 \\ \end{cases} . $ , then
[Roorkee 1988]
Options:
A) $ \underset{x\to 0+}{\mathop{\lim }},f(x)=1 $
B) $ \underset{x\to 0-}{\mathop{\lim }},f(x)=1 $
C) $ f(x) $ is discontinuous at $ x=0 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Clearly from curve drawn of the given function $ f(x) $ is discontinuous at $ x=0. $
BETA
