[MP PET 1995, 97]
x
B) $ x+1 $
C) $ x-1 $
D) $ 1-x $
Correct Answer: D
$ f(x)=\frac{x}{x-1}=\frac{1}{y}\Rightarrow \frac{1}{x-1}=\frac{y-1}{y} $ {Applying dividendo} $ \Rightarrow \frac{x-1}{-1}=\frac{y}{y-1},\Rightarrow -x+1=y. $
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