Functions Question 634

Question: Let $ g(x)=1+x-

[x] $ and $ f(x)= \begin{cases} & -1,,Ifx<0 \\ & 0,,If,x=0, \\ & 1,,ifx>0 \\ \end{cases} . $ then for all values of x the value of $ fog(x) $ [DCE 2005]

Options:

A) x

B) 1

C) $ f(x) $

D) $ g(x) $

Show Answer

Answer:

Correct Answer: B

Solution:

$ g(x)=1+{x} $ ; $ f{g(x)}=f{1+{x}} $ $ =f(k)=1 $ where, $ k=1+{x},1\le k<2 $