Functions Question 634
Question: Let $ g(x)=1+x-
[x] $ and $ f(x)= \begin{cases} & -1,,Ifx<0 \\ & 0,,If,x=0, \\ & 1,,ifx>0 \\ \end{cases} . $ then for all values of x the value of $ fog(x) $ [DCE 2005]
Options:
A) x
B) 1
C) $ f(x) $
D) $ g(x) $
Show Answer
Answer:
Correct Answer: B
Solution:
$ g(x)=1+{x} $ ; $ f{g(x)}=f{1+{x}} $ $ =f(k)=1 $ where, $ k=1+{x},1\le k<2 $