Functions Question 640
Question: If $ f(x)= \begin{cases} & \frac{\sin 2x}{5x},when,x\ne 0 \\ & k,\text{when }x=0 \\ \end{cases} . $ is continuous at $ x=0 $ , then the value of k will be
[AI CBSE 1991]
Options:
A) 1
B) $ \frac{2}{5} $
C) $ -\frac{2}{5} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \underset{x\to 0}{\mathop{\lim }}f(x)=\underset{x\to 0}{\mathop{\lim }},\frac{2\sin ,2x}{2x,.,5}=\frac{2}{5}=k. $
BETA
