[RPET 2002]
A) {0, 1}
B) {?1, 1}
C) R
D) $ R-{-2} $
Correct Answer: B
$ f(x)=\frac{x+2}{|x+2|} $ $ f(x)= \begin{cases} -1, \\ 1, \\ \end{cases} .\begin{matrix} x<-2 \\ x>-2 \\ \end{cases} $ \ Range of $ f(x) $ is $ {-1,,1} $ .
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