Functions Question 646

Question: The range of $ f(x)=\cos 2x-\sin 2x $ contains the set

[IIT Screening]

Options:

A) [2, 4]

B) [?1, 1]

C) [?2, 2]

D) [?4, 4]

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Answer:

Correct Answer: B

Solution:

$ f(x)=\sqrt{2},[ \sin ( \frac{\pi }{4}-2x ) ] $
$ \therefore -\sqrt{2}\le f(x)\le \sqrt{2} $ and $ [-1,1],\subset ,[-\sqrt{2},\sqrt{2}] $ .