[AMU 1999]
A) [1, 3]
B) $ [ \frac{1}{3},1 ] $
C) (1, 3)
D) $ ( \frac{1}{3},\ 1 ) $
Correct Answer: B
$ f(x)=\frac{1}{2-\sin 3x},\sin 3x\in [-1,1] $ Hence $ f(x) $ lies in $ [ \frac{1}{3},1 ] $ .
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