SATHEE: Functions Question 647

Functions Question 647

Question: Range of the function $ \frac{1}{2-\sin 3x} $ is

[AMU 1999]

Options:

A) [1, 3]

B) $ [ \frac{1}{3},1 ] $

C) (1, 3)

D) $ ( \frac{1}{3},\ 1 ) $

Show Answer

Answer:

Correct Answer: B

Solution:

$ f(x)=\frac{1}{2-\sin 3x},\sin 3x\in [-1,1] $ Hence $ f(x) $ lies in $ [ \frac{1}{3},1 ] $ .

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Functions Question 647

Question: Range of the function $ \frac{1}{2-\sin 3x} $ is

Options:

Answer:

Solution:

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