A) (?1, 1)
B) [0, 1]
C) [?1, 0]
D) (?1, 2)
Correct Answer: B
Let $ y={{\sin }^{-1}}\sqrt{x}\Rightarrow \sqrt{x}=\sin y $
$ \Rightarrow x={{\sin }^{2}}y,\therefore 0\le x\le 1 $
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