Functions Question 691
Question: $ \underset{x\to 0}{\mathop{\lim }},\frac{1-\cos 2x}{x}= $
[MNR 1983]
Options:
A) 0
B) 1
C) 2
D) 4
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{x\to 0}{\mathop{\lim }},\frac{x,.,2,{{\sin }^{2}}x}{x^{2}}=2.\underset{x\to 0}{\mathop{\lim }},{{( \frac{\sin x}{x} )}^{2}}\cdot \underset{x\to 0}{\mathop{\lim }},x=0 $ .
BETA
