Functions Question 701
Question: Let f:{ $ x,y,z $ } $ \to $ { $ 1,2,3 $ } be a one-one mapping such that only one of the following three statements is true and remaining two are false: $ f(x)\ne 2,f(y)=2,f(z)\ne 1 $ , then
Options:
A) $ f(x)\gt f(y)\gt f(z) $
B) $ f(x) \lt f(y) \lt f(z) $
C) $ f(y) \lt f(x) \lt f(z) $
D) $ f(y) \lt f(z) \lt f(x) $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Let $ f(x)\ne 2 $ be true and $ f(y)=2,f(z)\ne 1 $ are False
$ \Rightarrow f(x)\ne 2,f(y)\ne 2,f(z)=1 $
$ \Rightarrow f(x)=3,f(y)=3,f(z)=1 $ but then function is many one, similarly to other cases.
BETA
