Functions Question 702
If $ f:R\to R,f(x)= \begin{cases} x|x| -4,,x\in \mathbb{Q} \ x|x| -\sqrt{3},,x\notin \mathbb{Q} \end{cases}, . $ then $ f(x) $ is
Options:
A) one-to-one and onto
B) Many to one and one to many
C) one to one and onto
D) Many to one and onto
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ f(2)=f( {3^{1/4}} )\Rightarrow $ many to one function And $ f(x)\ne -\sqrt{3}\forall x\in R\Rightarrow $ into function
BETA
